Final answer:
The input cutoff low-frequency is determined by the formula for cutoff frequency involving capacitive reactances, but due to insufficient information provided, the exact frequency cannot be calculated.
Step-by-step explanation:
To find the input cutoff low-frequency, an understanding of the relationship between capacitive reactance and frequency is necessary. The formula to calculate the cutoff frequency is given as:
fo = 1 / (2π√(Cbc × Cbe))
Where Cbc and Cbe are the capacitances of the base-collector and base-emitter junctions, respectively. Given that Cbc = 22 pF and Cbe = 22 pF, we find:
fo = 1 / (2π√(22 pF × 22 pF))
This formula will yield the input cutoff low-frequency in Hertz. However, since the question does not provide the necessary constants or all of the required information to solve it fully, we cannot compute the exact frequency. The information provided may be relevant to other parts of the topic or examples, but it is not sufficient to complete this specific calculation.