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An electromagnetic wave in free space, having an angular frequency of 5rad/s, has an electric field given by: E = 3sin(x)e⁻ʲ²ᶻ y [V/m] Find the corresponding magnetic field.
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An electromagnetic wave in free space, having an angular frequency of 5rad/s, has an electric field given by:

E = 3sin(x)e⁻ʲ²ᶻ y [V/m] Find the corresponding magnetic field.

User Kevin Nagurski
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1 Answer

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Final answer:

The corresponding magnetic field in an electromagnetic wave can be found using the equation B = (E/c), where E is the electric field and c is the speed of light in a vacuum.

Step-by-step explanation:

The magnetic field is related to the electric field in an electromagnetic wave by the equation:

B = (E/c)

Where E is the electric field and c is the speed of light in a vacuum.

Therefore, the corresponding magnetic field in this case would be:

B = (3sin(x)e⁻ʲ²ᶻ y)/(3 x 10^8 m/s)

User Stianlagstad
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