Question

A circuit is built with a voltage source and two resistors: 80 Ω, and 90 Ω.. What is the maximum resistance possible if both resistors must be part of the circuit?

Answer 1

The maximum resistance in a circuit with two resistors in parallel is 36 Ω.

Step-by-step explanation:

In a circuit with two resistors in parallel, the total resistance is equal to the reciprocal of the sum of the reciprocals of the individual resistances. The formula for calculating the total resistance in a parallel circuit is:

1/R_total = 1/R1 + 1/R2

Given that the resistances of the two resistors are 80 Ω and 90 Ω, we can substitute the values into the equation:

1/R_total = 1/80 + 1/90

Simplifying the equation gives us:

R_total = 36 Ω

Therefore, the maximum resistance possible in this circuit is 36 Ω.

Answer 2

The maximum resistance in a circuit with two resistors in parallel is approximately 44.62 Ω when the resistors have resistance values of 80 Ω and 90 Ω.

Step-by-step explanation:

In a circuit with two resistors in parallel, the maximum resistance possible is when both resistors have the same resistance value. In this case, the resistances of the two resistors are 80 Ω and 90 Ω.

To find the maximum resistance, we can use the formula for the total resistance of resistors in parallel:

1/RTotal = 1/R1 + 1/R2

Substituting the given resistance values, we have:

1/RTotal = 1/80 + 1/90

Calculating this expression gives:

RTotal = 1 / (1/80 + 1/90)

Using a calculator, the maximum resistance is approximately 44.62 Ω.