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The carrier c(t)=10 cos 2πft is frequency modulated (FM) by the signal m(t)=3 cos 2000πt, where f = 10⁶ Hz. The peak-frequency deviation is 5 kHz. Determine the frequency deviation constant.

User MoritzLost
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Final answer:

The frequency deviation constant is equal to the peak-frequency deviation divided by the peak amplitude of the modulating signal.

Step-by-step explanation:

Frequency modulation (FM) is a method of encoding information onto a carrier wave by varying its frequency. In this case, the carrier wave is represented by c(t) = 10 cos(2πft), where f is the frequency of the carrier wave, which is 10^6 Hz. The signal m(t) = 3 cos(2000πt) is modulating the carrier wave.

The peak-frequency deviation is the maximum change in frequency due to modulation. In this case, the peak-frequency deviation is 5 kHz.

The frequency deviation constant, represented by Δf/Δm, is equal to the peak-frequency deviation divided by the peak amplitude of the modulating signal. In this case, the peak amplitude of the modulating signal is 3.

Therefore, the frequency deviation constant is 5 kHz / 3.

User Nikhil Redij
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