Question

That is the output of the following code? Explain why the function Swap behaves the way it does.

void Swap (int x, int y);
int main(void)
int x=1;
int y=2;

Swap (x, y); printf ("x=%dy=%d\\",x,y); }

void Swap (int y, int x){
int temp;
temp =x;
x=y;
y= temp;
}

Answer 1

The output of the code is x=1 y=2. The Swap function does not interchange the values of x and y because parameters are passed by value in C.

Step-by-step explanation:

The output of the given code is x=1 y=2. The function Swap does not actually interchange the values of x and y in the main function. This is because in C, parameters are passed by value, which means that the values of x and y are copied to the Swap function, and any changes made to x and y within the Swap function do not affect the original variables in the main function. Therefore, the values of x and y remain unchanged after calling the Swap function.