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A 15-KV:175-KV, 125-MVA, 60-Hz Single-Phase Transformer Has Primary And Secondary Impedances Of 0.0095 + J0.063 Per Unit Each. The Magnetizing Impedance Is J148 Per Unit. All Quantities Are In Per Unit On The Transformer Base. Calculate The Primary And Secondary Resistances And Reactances And The Magnetizing Inductance (Referred To The Low-Voltage Side) in ohms and henrys

User Marschro
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Final answer:

To calculate the primary and secondary resistances and reactances, multiply the per unit values with the base impedance. For the magnetizing inductance, take the square root of the square of the per unit magnetizing impedance multiplied by the base impedance.

Step-by-step explanation:

The primary and secondary resistances and reactances for a 15-kV:175-kV, 125-MVA, 60-Hz single-phase transformer can be calculated using the given impedance values. The primary resistance (R1) and reactance (X1) can be found by multiplying the per unit values with the base impedance of the transformer. Similarly, the secondary resistance (R2) and reactance (X2) can be calculated using the per unit values and base impedance. The magnetizing inductance can be determined by taking the square root of the square of the per unit magnetizing impedance multiplied by the base impedance.

Primary resistance (R1) = 0.0095 * base impedance

Primary reactance (X1) = 0.063 * base impedance

Secondary resistance (R2) = 0.0095 * base impedance

Secondary reactance (X2) = 0.063 * base impedance

Magnetizing inductance = sqrt((0.148 * base impedance) ^ 2)

Substituting the given base impedance values, we can calculate the primary and secondary resistances and reactances, as well as the magnetizing inductance in ohms and henrys.

User Dino Tw
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