Question

The following program fragments have syntax errors and therefore will not compile. Assume that all variables have been properly declared. Fix the errors so that the fragments will not cause compiler errors.

a.
i=0;
j=0;
while ( i <5 ) {
j = j +1;
i = j >> 1
}

Answer 1

The syntax error in the code fragment is the missing semicolon at the end of the line. Adding a semicolon will fix the error.

Step-by-step explanation:

The syntax error in this code fragment is the missing semicolon at the end of the statement i = j >> 1. To fix the error, we need to add a semicolon at the end of the line.

Here is the corrected code:

i = 0; j = 0; while (i < 5) { j = j + 1; i = j >> 1; }

Now, the code will compile without any errors.