Final answer:
The power factor, average power, and reactive power of an AC motor with given impedance and RMS voltage can be calculated using the formulas for power factor (PF = R / |Z|), average power (Pave = Vrms^2 * PF / R), and reactive power (Q = Vrms * Irms * sin(φ)), respectively.
Step-by-step explanation:
The power factor, the average power, and the reactive power of an AC motor with impedance ZL = {3.2 + j1.60} Ω supplied by a 220 V RMS, 60 Hz source can all be determined from the given impedance and voltage.
Power Factor Calculation:
The power factor (PF) is the ratio of the resistance (R) to the magnitude of the impedance (|Z|). The magnitude of Z is √(R^2 + (XL - XC)^2). Since the motor doesn't seem to have capacitive reactance (XC), the power factor formula simplifies to:
PF = R / |Z| = 3.2 Ω / √(3.2^2 + 1.6^2) Ω
Average Power Calculation:
The average power (Pave) is given by Pave = Vrms^2 * PF / R. Upon solving this with the given voltage and calculated PF, we find the average power in kilowatts.
Reactive Power Calculation:
The reactive power (Q) is the product of the RMS voltage, the RMS current, and the sine of the phase angle, which corresponds to Q = Vrms * Irms * sin(φ). Since sin(φ) in this case is equivalent to the imaginary part of the impedance over the magnitude of the impedance, we can calculate the reactive power in kilovolt-amperes reactive (kVAR).