Final answer:
The electric potential at point (2, π/4, 4) is approximately 5.513 V, and the electric field at the same point is approximately 0.4468 N/C.
Step-by-step explanation:
To find the potential (V) at point (2, π/4, 4), we can use the formula for the electric potential due to a dipole:
= /³
Where is the constant ₀ / (4), is the dipole moment, is the cosine of the angle between the dipole moment and the vector, and is the distance between the dipole and the point of interest.
Plugging in the given values, we have:
= (10⁻¹/36) * (20) * (cos(0) / (4² + 0.6908² + 0.7333²)³)
≈ 5.513 V
To find the electric field (E) at the same point, we can use the formula:
= / ³
Plugging in the values:
= (10⁻¹/36) * (20) / (4² + 0.6908² + 0.7333²)³
≈ 0.4468 N/C