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A common-emitter amplifier whose BJT has β=100 operates in the active region, with R=Rₑ =10kΩ. The biasing scheme has resistors RB₁=1MΩ,RB₂=0.7MΩ. A smallsignal input with Rsig=10kΩ is fed into the amplifier. The output voltage is taken from a load resistor Rₗ =10kΩ.

(a) Draw the small-signal equivalent circuit of common-emitter amplifier. Assume rπ= 5kΩ,r₀=100kΩ
(b) Find the input resistance Rᵢₙ and output resistance Rₒᵤₜ of the small-signal circuit
(c) Find the overall voltage gain v₀ /vₛᵢ. Assume gm=3.7 mA/V.

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Final answer:

The question involves determining the small-signal equivalent circuit of a common-emitter amplifier, calculating input and output resistances, and finding the overall voltage gain by considering transistor parameters, biasing resistors, and load resistance.

Step-by-step explanation:

The student's question relates to the analysis of a small-signal equivalent circuit for a common-emitter amplifier and determining its input and output resistances as well as the overall voltage gain. This kind of problem is typically found in electrical engineering or electronic engineering courses, where students learn about the behavior of transistors in amplifier configurations.

To draw the small-signal equivalent circuit, we represent the transistor as its small-signal model, which includes the parameters rπ, r0, and gm. The biasing resistors RB1 and RB2 form a voltage divider bias scheme, and the input resistance Rsig is represented feeding into the base of the transistor. The output voltage is taken across the load resistor RL.

The input resistance Rin of the small-signal circuit is a function of both the base resistors and rπ, considering the base-emitter junction of the transistor. The output resistance Rout is primarily influenced by RL and r0.

For the voltage gain v0/vsig, we consider the transconductance gm as well as the input and load resistances, among other factors such as the internal resistance of the transistor r0.

User Pedro Dusso
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