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An offset impedance relay has a characteristic equation ∣Z+K₄∣=(K₁+K₂). Show that this equation describes a circle in the R−X plane. Determine the location of its center (origin) and its radius.

User Nick Bauer
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Final answer:

The characteristic equation \( |Z+K_4| = (K_1+K_2) \) represents a circle in the R-X plane with its center at the negative of the real and imaginary parts of \( K_4 \) and a radius of \( K_1 + K_2 \).

Step-by-step explanation:

The characteristic equation of an offset impedance relay given by \( |Z+K_4| = (K_1+K_2) \) does indeed describe a circle in the R-X plane where R represents resistance and X represents reactance. To show this, we can start by expressing Z as a complex number Z = R + jX, where R is the real part (resistance) and jX is the imaginary part (reactance), with j representing the imaginary unit.

Now, let's rewrite the characteristic equation as:

\( |(R + jX) + K_4| = K_1 + K_2 \)

Assuming that \( K_4 \) is also a complex number, \( K_4 = a + jb \), the equation becomes:

\( |(R + a) + j(X + b)| = K_1 + K_2 \),

which simplifies to:

\( \sqrt{(R + a)^2 + (X + b)^2} = K_1 + K_2 \).

Squaring both sides we get:

\( (R + a)^2 + (X + b)^2 = (K_1 + K_2)^2 \),

which is the standard form of the equation of a circle with the center at (-a, -b) and the radius equal to \( K_1 + K_2 \).

User Amol Manthalkar
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