Final answer:
The voltage required to move 3 coulombs of charge in 2 seconds is 357 volts.
Step-by-step explanation:
To find the voltage required to move 3 coulombs of charge in 2 seconds, we need to calculate the energy using the formula E = qV, where E is the energy, q is the charge, and V is the voltage. In this case, q = 3 C and the time t = 2 s. Substituting these values into the given equation W(t) = 20t⁴ + 18t + 1, we can solve for V.
First, calculate the energy E using the formula E = qV:
E = (3 C)(V)
Next, substitute the equation W(t) = 20t⁴ + 18t + 1 into the equation E = qV:
20t⁴ + 18t + 1 = 3(V)
Now, solve for V:
V = (20t⁴ + 18t + 1) / 3
Plugging in t = 2:
V = (20(2)⁴ + 18(2) + 1) / 3
V = (320 + 36 + 1) / 3
V = 357 volts