Question

Note: Read this problem statement carefully! Build a circuit suitable for this application using an ac source of 115 volts, f=60 Hz and is considered for series R−C ac for circuit analysis: Given: Vi=115 volts ac, single phase (1−Φ),60c/s,R=10KQ ac; C=10 mili F. Mark Vo in your circuit across the capacitor; f=60c/s Ground your circult appropriately. Conduct AC circuit analysis of this simple series R-C circult

Find
1) Impedance Z of this circuit

Answer 1

The impedance (Z) of the R-C circuit can be found using the formula Z = sqrt(R^2 + (X1 - Xc)^2), where R is the resistance, X1 is the inductive reactance, and Xc is the capacitive reactance.

Step-by-step explanation:

The impedance (Z) of the R-C circuit can be found using the formula Z = sqrt(R^2 + (X1 - Xc)^2), where R is the resistance, X1 is the inductive reactance, and Xc is the capacitive reactance. In this circuit, R = 10kQ, X1 = 0 (since it's a pure resistor), and Xc = 1/(2πfC), where f is the frequency and C is the capacitance. Plugging in the values, we get:

Z = sqrt((10k)^2 + (0 - 1/(2π * 60 * 10^(-3)))^2)

= sqrt(100 MQ + (0 - 26529. stands for Q, caps)/(60 * 10^(-3))^2) (1M = 10^6)

= sqrt(100 MQ + (26529. stands for Q, caps)^2 / 36 * 10^(-6))

= sqrt(100 MQ + (26529. stands for Q, caps)^2 / 36 * 10^(-6))