Question

Given the following information regarding a series R-L-C circuit, find the parallel equivalent circuit. R = 1200 Ω , C = 1500pF, RI = 200Ω and L = 2.5 H, the frequency of the applied sine wave is 2500Hz at an amplitude of 3Vp-p

Answer 1

The question involves calculating the parallel equivalent of a series R-L-C circuit at a specified frequency using reactance and impedance formulas and then converting the series components to their parallel equivalents.

Step-by-step explanation:

To find the parallel equivalent of a given R-L-C circuit, and given the values R = 1200 Ω, C = 1500pF, RI = 200Ω, L = 2.5 H, and a sine wave frequency of 2500Hz with an amplitude of 3Vp-p, one must perform a series of calculations that typically involve the formulas for reactance and impedance of RLC circuits.

The inductive reactance (XL) would be calculated using XL = 2πfL, and the capacitive reactance (XC) can be found with XC = 1 / (2πfC). The total impedance (Z) of the circuit can be calculated with Z = √(R2 + (XL - XC)2).

However, converting the series RLC components to their parallel equivalents would require the usage of the transformation equations which are not a straightforward application but based on the particular requirements of maintaining the same impedance at a particular frequency or within a range of frequencies.