Question

Si P(A) = 0,38, P(B) = 0,83 y P(A ∩ B) = 0,27; entonces P(A ∪ B) = ________.

a. 0.73
b. 0.94
c. 1.21
d. 0.46

Answer 1

The probability of either event A or B occurring, P (A ∪ B), is calculated by summing the probabilities of A and B and then subtracting the probability of A and B occurring together. In this case, P (A ∪ B) equals 0.94.

Step-by-step explanation:

To find the probability of either event A or event B occurring (denoted as P (A ∪ B)), we use the formula:

P (A ∪ B) = P(A) + P(B) − P (A ∩ B)

Given P(A) = 0.38, P(B) = 0.83, and P (A ∩ B) = 0.27, we can calculate:

P (A ∪ B) = 0.38 + 0.83 − 0.27 = 0.94

Therefore, the correct answer is 0.94.