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Find the magnetic vector potential, A, and magnetic flux density, B, caused by a length of 2ℓ of current I=I0​a^z​ at the midpoint of the line.

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Final answer:

For both the magnetic vector potential
(\(A\)) and the magnetic flux density
(\(B\)):

1. **Magnetic Vector Potential
(\(A\)):**


\[ A_z(\rho, \phi, z=0) = (\mu_0 I_0)/(2\pi) (1)/(\rho) \]

2. **Magnetic Flux Density
(\(B\)):**


\[ B_\rho = -(\mu_0 I_0)/(2\pi) (1)/(\rho^2) \]


\[ B = B_\rho a^\rho \]

Step-by-step explanation:

To find the magnetic vector potential
(\(A\)) and magnetic flux density
(\(B\)) caused by a length of
\(2\ell\) of current
\(I=I_0 a^z\) at the midpoint of the line, we can use the Biot-Savart law and the relationship between
\(A\) and
\(B\) in the context of magnetostatics.

1. **Magnetic Vector Potential
(\(A\)):**

The magnetic vector potential
(\(A\)) is given by the line integral of the magnetic field
(\(B\)) along a closed loop. For an infinitely long straight current, the magnetic vector potential can be expressed in cylindrical coordinates as follows:


\[ A(\rho, \phi, z) = (\mu_0 I)/(4\pi) \int (d\phi)/(\rho) \]

Since the current is along the
\(z\)-axis., the contribution to
\(A\) will be along the
\(z\)-axis.


\[ A_z(\rho, \phi, z) = (\mu_0 I_0)/(4\pi) \int_0^(2\pi) (d\phi)/(\rho) \]

Evaluating the integral will give you the expression for
\(A_z\).

2. **Magnetic Flux Density
(\(B\)):**

The magnetic flux density
(\(B\)) is related to the magnetic vector potential
(\(A\)) by the curl operation.


\[ B = \\abla * A \]

In cylindrical coordinates, this simplifies to:


\[ B_\rho = (1)/(\rho) (\partial A_z)/(\partial \phi) \]

You can find the expression for
\(B_\rho\) using the derived expression for
\(A_z\).

The magnetic flux density
\(B\) is then given by
\(B = B_\rho a^\rho\).

Note: The result will depend on the specific geometry of your problem, and in this case, the length of the current
(\(2\ell\)) and the location where you are evaluating the magnetic field are crucial.

User Bbx
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