Question

Three resistors RA, RB, and RC , respectively, are connected in series to a 110 V source. RA = 40 ohm and the voltage across B, VB = 35 V. The current i = 0.7 amp.

What is the resistance in B?

Answer 1

The resistance in resistor B is 50 ohms.

Step-by-step explanation:

In a series circuit, the total resistance is equal to the sum of the individual resistances. In this case, the resistors RA, RB, and RC are connected in series, so the total resistance is R total = RA + RB + RC. The voltage across resistor B, VB, is given as 35 V. The current through the circuit is i = 0.7 A. To find the resistance of B, we can use Ohm's Law, which states that resistance is equal to voltage divided by current: RB = VB / i.

Substituting the given values into the formula, we have RB = 35 V / 0.7 A = 50 ohms. Therefore, the resistance in resistor B is 50 ohms.