124k views
3 votes
Consider a step index fiber with n1​=1.449,n2​=1.445, and a=25μm, please estimate the number of modes that can be propagated in this optical fiber. Assume that the wavelength is 1.5 micron.

User Pynchia
by
7.5k points

1 Answer

3 votes

Final answer:

The estimated number of modes that can be propagated in this optical fiber is approximately 41.

Step-by-step explanation:

In order to estimate the number of modes that can be propagated in the step index fiber, we can use the formula:

Number of modes = (2πa / λ) × √(n1^2 - n2^2)

where a is the core radius, λ is the wavelength, n1 is the refractive index of the core, and n2 is the refractive index of the cladding.

Plugging in the values given in the question, we have:

Number of modes = (2π × 25μm / 1.5μm) × √(1.449^2 - 1.445^2) ≈ 41

Therefore, the estimated number of modes that can be propagated in this optical fiber is approximately 41.

User Oleksii Balenko
by
9.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.