Question

An electron moves with a velocity 1×10³m/s in a magnetic field of induction 0.3T at an angle 30o. If me​ of electrons 1.76×10¹¹C/kg, the radius of the path is nearly

A 10⁻⁸m
B 2×10⁻⁸m
C 10⁻⁶m
D 10⁻¹⁰m

Answer 1

The radius of the path followed by an electron moving in a magnetic field can be calculated using the formula r = m*v / (e*B*sin(theta)). Plugging in the given values, we find that the radius of the path is approximately 2x10⁻⁸ m.

Step-by-step explanation:

To find the radius of the path followed by an electron moving in a magnetic field, we can use the formula for the radius of a charged particle's path in a magnetic field, which is given by r = m*v / (e*B*sin(theta)).

Here, r is the radius of the path, m is the mass of the electron, v is the velocity of the electron, e is the charge of the electron, B is the magnetic field strength, and theta is the angle between the velocity vector and the magnetic field.

Plugging in the given values, we have r = (1.76x10⁻¹¹ kg * 1x10³ m/s) / (1.6x10⁻¹⁹ C * 0.3 T * sin(30°)) ≈ 2x10⁻⁸ m. Therefore, the radius of the path is approximately 2x10⁻⁸ m.