Question

Modern integrated circuits on-chip temperatures reach 100∘C. At this temperature, if you want to turn-off the current by a factor of 105 in a FET. What is the absolute theoretical minimum change in gate voltage that is required?

Answer 1

The minimum change in the gate voltage required to turn off the current in a FET by a factor of 105 at 100°C can be estimated using the equation I = I0e(qV/kT), where constants are known and the temperature is given in kelvins.

Step-by-step explanation:

The question is asking for the theoretical minimum change in gate voltage to reduce the current in a Field Effect Transistor (FET) by a factor of 105. This involves semiconductor physics and the electronic behavior of devices under varying temperatures and voltages. The relationship between the current and voltage in a transistor can be described by the equation I = I0e(qV/kT), where I is the current, I0 is the reverse saturation current, V is the voltage across the transistor, q is the charge of an electron, k is Boltzmann's constant, and T is the temperature in kelvins.

At a temperature of 100°C, which is 373 K, and wanting to reduce the current by a factor of 105, the minimum gate voltage change can be calculated using this ideal relationship. Factors such as non-idealities in real circuits, thermal voltage, and adjustments for subthreshold swing should also be considered for an accurate analysis.