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A PIN-TIA receiver operating at 1550 nm has η=0.60, a transimpedance of 1200Ω, and an electrical bandwidth of Be​=2.5GHz. With no light input, the standard deviation of its output noise voltage is 2mV.

a) What is the noise spectral density of its output voltage in V²/Hz when no light is input?

User Sajiv
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Final answer:

The noise spectral density of the output voltage is approximately 8 x 10^-9 V²/Hz.

Step-by-step explanation:

The noise spectral density of the output voltage can be calculated using the formula:

Noise Spectral Density = Standard Deviation2 / Bandwidth

Given that the standard deviation of the output noise voltage is 2mV and the electrical bandwidth is 2.5GHz, we can substitute these values into the formula:

Noise Spectral Density = (2mV)2 / 2.5GHz

Converting the unit of standard deviation to V and simplifying the expression, the noise spectral density of the output voltage is approximately 8 x 10-9 V²/Hz.

User Steenslag
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