Question

A certain practical dc voltage source can provide a current of 13.5 A when it is (momentanly) short-circuled, and can provide of 12 W to a 20Ω load. Find

(a) The open-arcult voltage

Answer 1

The open-circuit voltage of the practical dc voltage source is 20 V.

Step-by-step explanation:

To find the open-circuit voltage, we can use the power formula P = IV, where V is the source voltage. We know that the source can provide a current of 13.5 A when short-circuited and can provide 12 W to a 20 Ω load. So, we can calculate the voltage as follows:

P = IV

12 W = I * 20 Ω

12 = I * 20

0.6 A = I

V = P/I

V = 12 W / 0.6 A = 20 V

Therefore, the open-circuit voltage is 20 V.