Question

Calculate the output power in watts of 1-ph full-wave rectifier supplying a constant dc current load of 10A if input ac voltage source is 120V. Use one decimal accurancy

Answer 1

The output power of a 1-phase full-wave rectifier supplying a 10 A load from a 120 V AC source is theoretically 1200 W or 1.2 kW, assuming ideal conversion with no losses.

Step-by-step explanation:

To calculate the output power of a 1-phase full-wave rectifier supplying a constant DC current load of 10 A from an input AC voltage source of 120 V, you can use the power formula P = IV, where I is the current and V is the voltage.

However, in a full-wave rectifier, the AC input voltage is converted to DC output voltage, which is less than the peak input voltage due to the diode voltage drop and the transformer's characteristics. The exact DC output voltage can vary, and it is not provided in the question. Assuming an ideal case with no voltage drop and perfect conversion, which is not practical but will provide an upper limit to the possible output power:

Output Power (P) = DC Current (I) × DC Voltage (V)

P = 10 A × 120 V

P = 1200 W or 1.2 kW

This calculation does not take into account real-world inefficiencies and assumes an ideal rectification process. Always remember to account for non-ideal conditions in practical applications, which would lower the actual output power.

Answer 2

The output power of a full-wave rectifier with a 10A DC current load and a 120V AC input is 1200W or 1.2kW when using the formula P = IV and assuming perfect conversion of AC to DC without losses.

Step-by-step explanation:

The subject of this question is physics, and it is typically at the high school level. To calculate the output power of a 1-phase full-wave rectifier supplying a constant DC current load, we use the formula P = IV, where P is the power in watts, I is the current in amperes, and V is the source voltage in volts. Since the rectifier is converting AC to DC, we consider the DC output voltage to be equivalent to the peak-to-peak value of the input AC voltage because in a full-wave rectifier, both halves of the input waveform are used.

Therefore, if we ignore the voltage drop across the rectifying elements and assume perfect conversion, the output power in watts is simply the product of the current and voltage. Given a constant DC current load of 10A and an input AC voltage source of 120V, the output power P would be:

P = I × V = 10A × 120V = 1200W or 1.2kW using one decimal accuracy.