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in an acceptance sampling plan devoloped for lots centaining 1,700 units, the sample size n is 105 . The percent defective of the incoming lots is 6%, and ze probabily of acceptance is 0.75. What is the average oulgoing quatity? The average outgoing pualiy in peroent defective___is (Flound your response to three decinal places)

User Rfreytag
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Final answer:

The average outgoing quantity can be calculated using the formula (Sample size / Lot size) * Defective rate * (1 - Probability of acceptance). In this case, the average outgoing quantity is 0.0015 units. The average outgoing quality in percentage defective is 0.15%.

Step-by-step explanation:

The average outgoing quantity in an acceptance sampling plan can be calculated using the following formula:

Average outgoing quantity = (Sample size / Lot size) * Defective rate * (1 - Probability of acceptance)

In this case, the sample size (n) is 105, the lot size is 1,700 units, the defective rate is 6%, and the probability of acceptance is 0.75. Plugging in these values into the formula, we get:

Average outgoing quantity = (105 / 1700) * 0.06 * (1 - 0.75) = 0.006 * 0.25 = 0.0015

Therefore, the average outgoing quantity is 0.0015 units.

The average outgoing quality in percentage defective can be calculated by multiplying the average outgoing quantity by 100. So, the average outgoing quality in percentage defective is 0.0015 * 100 = 0.15%.

User Ramakrishna Guttha
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