Question

I need help with my math

Answer 1

We are given the following equation

`5x-3y=15`

There are multiple ways to graph this equation.

One method is by finding the x-intercept and y-intercept of the equation.

The other method is to find the slope and the y-intercept of the equation.

Let us find the x-intercept and y-intercept of the equation.

x-intercept:

This is the point where the line intersects the x-axis.

To find the x-intercept, substitute y = 0 into the equation.

`\begin{gathered} 5x-3y=15 \\ 5x-3(0)_{}=15 \\ 5x=15 \\ x=(15)/(5) \\ x=3 \end{gathered}`

So, the x-intercept is 3

y-intercept:

This is the point where the line intersects the y-axis.

To find the y-intercept, substitute x = 0 into the equation.

`\begin{gathered} 5x-3y=15 \\ 5(0)-3y=15 \\ -3y=15 \\ y=(15)/(-3) \\ y=-5 \end{gathered}`

So, the y-intercept is -5

Therefore, the correct graph is the one that intersects the x-axis at 3 and the y-axis at -5