Question 1

A 60 W light bulb has a resistance of 880 Ω

Calculate the CURRENT.
Write your answer in Amps to TWO SIGNIFICANT FIGURES

Question 2

$\bf{ \underline{Given:- }}$

$\sf{• \: Power \: (P) = 60 \: w}$

$\sf{• \: Resistance \: (R) = 880 \: Ω}$

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$\bf{ \underline{To \:  Find :- }}$

$\sf• \: The \: Current \: (I).$

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$\huge\bf{ \underline{ Solution :- }}$

$\sf We \: know \: that,$

$\bf \red {\bigstar{ \: P = I^(2) R}}$

$\rightarrow \sf 60 = I^(2) * 880$

$\rightarrow \sf (60)/(880) = I^(2)$

$\rightarrow \sf I^(2) = 0.0681$

$\rightarrow \sf I = √(0.0681)$

$\rightarrow \sf I = 0.261 \: \: (approx.)$

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$\bf The \: \: value \: \: of \: \: I \: \: is \: \: 0.261 \: \: Amps. \: \: (approx.)$