Question

A 60 W light bulb has a resistance of 880 Ω

Calculate the CURRENT.
Write your answer in Amps to TWO SIGNIFICANT FIGURES

Answer 1

`\bf{ \underline{Given:- }}`

`\sf{• \: Power \: (P) = 60 \: w}`

`\sf{• \: Resistance \: (R) = 880 \: Ω}`

`\\`

`\bf{ \underline{To \:  Find :- }}`

`\sf• \: The \: Current \: (I).`

`\\`

`\huge\bf{ \underline{ Solution :- }}`

`\sf We \: know \: that,`

`\bf \red {\bigstar{ \: P = I^(2) R}}`

`\rightarrow \sf 60 = I^(2) * 880`

`\rightarrow \sf (60)/(880) = I^(2)`

`\rightarrow \sf I^(2) = 0.0681`

`\rightarrow \sf I = √(0.0681)`

`\rightarrow \sf I = 0.261 \: \: (approx.)`

`\\`

`\bf The \: \: value \: \: of \: \: I \: \: is \: \: 0.261 \: \: Amps. \: \: (approx.)`