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List Solve the equation in the complex nun x²-16x+73=0

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Final answer:

The solutions to the equation x² - 16x + 73 = 0 are x = 8 ± 3i.

Step-by-step explanation:

This expression is a quadratic equation of the form ax² + bx + c = 0, where the constants are a = 1, b = -16, and c = 73. To solve this equation, we can use the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac))/(2a)

Plugging in our values, we get:

x = (-(-16) ± sqrt((-16)^2 - 4(1)(73)))/(2(1))

Simplifying further, we have:

x = (16 ± sqrt(256 - 292))/(2)

x = (16 ± sqrt(-36))/(2)

Since we have a negative number under the square root, we know that the solutions to this equation will be complex numbers. Therefore, the solutions to the equation x² - 16x + 73 = 0 are:

x = (16 ± 6i)/2

Simplifying, we get:

x = 8 ± 3i

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