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Assume the kinetic energy of electron and photon energy is same ( E=1eV). Compute the de Broglie wavelength and momentum associated with an electron and photon.

User Srinu
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Final answer:

To compute the de Broglie wavelength and momentum for an electron and photon with the same energy of 1eV, one can use the relationship between energy and momentum for a photon (E=pc) and the kinetic energy formula for an electron (KE=(1/2)mv^2). Photon momentum is given in eV*s/m, and the de Broglie wavelength is calculated using Planck's constant. For an electron, the momentum is obtained from its velocity, which is derived from its kinetic energy.

Step-by-step explanation:

Calculating de Broglie Wavelength and Momentum of Electron and Photon

Given that the kinetic energy (KE) of an electron and a photon is the same, with E=1eV, let's calculate the de Broglie wavelength and the momentum for each.

Photon

For the photon, the energy E is related to the momentum p through the equation E = pc, where c is the speed of light. With E=1eV:

p = 1eV / (3.00 × 10^8 m/s)

Photon momentum is calculated in units of eV*s/m. To find the de Broglie wavelength (λ), we use λ = h/p, where h is Planck's constant.

Electron

m is the electron's mass = 9.11 × 10^-31 kg

p = √(2 * m * KE)

With this momentum, the electron's de Broglie wavelength can be calculated as mentioned before.

User GullerYA
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