Final answer:
To compute the de Broglie wavelength and momentum for an electron and photon with the same energy of 1eV, one can use the relationship between energy and momentum for a photon (E=pc) and the kinetic energy formula for an electron (KE=(1/2)mv^2). Photon momentum is given in eV*s/m, and the de Broglie wavelength is calculated using Planck's constant. For an electron, the momentum is obtained from its velocity, which is derived from its kinetic energy.
Step-by-step explanation:
Calculating de Broglie Wavelength and Momentum of Electron and Photon
Given that the kinetic energy (KE) of an electron and a photon is the same, with E=1eV, let's calculate the de Broglie wavelength and the momentum for each.
Photon
For the photon, the energy E is related to the momentum p through the equation E = pc, where c is the speed of light. With E=1eV:
p = 1eV / (3.00 × 10^8 m/s)
Photon momentum is calculated in units of eV*s/m. To find the de Broglie wavelength (λ), we use λ = h/p, where h is Planck's constant.
Electron
m is the electron's mass = 9.11 × 10^-31 kg
p = √(2 * m * KE)
With this momentum, the electron's de Broglie wavelength can be calculated as mentioned before.