Question

Force F = F, i+ Fyj acts on a particle that

undergoes a displacement of 5 = 5x ^ + sy 3
where Fx = 3 N, Fy = -3 N, Sx = 4 m, and
Sy = 1 m.
Find the work done by the force on the particle.
Answer in units of J.

Answer 1

The work done by the force on the particle is 9 Joules, calculated using the dot product of force and displacement vectors.

Step-by-step explanation:

The work done by a force on a particle during a displacement is calculated using the dot product of the force vector and the displacement vector. In this particular question, the force vector is F = Fxi + Fyj with Fx = 3 N and Fy = -3 N, and the displacement vector is s = sxi + syj with sx = 4 m and sy = 1 m.

The work done (W) can be computed as:

W = Fxsx + Fysy = (3 N)(4 m) + (-3 N)(1 m) = 12 J - 3 J = 9 J.

Therefore, the work done by the force on the particle is 9 Joules.