Question

What is the output of executing the following Matlab code? clear for i-1:5 for j-i:5 M(i,j)-i+j M(j, i)s M(ij); end end M(4.3) 19 Involving fprintf and nested for-loop commands, write a Matlab seript to print the following pattern: 12 123 1234 123456 234567 Answer % 7 rows altogether % this is important to set the length of each row. % print the numbers on each row, number-by-number for i-1:7 for j i fprintf("%d', j) end rintfC n) %start from a new line. end

Answer 1

The first part of the question is invalid due to syntax errors in the MATLAB code. The corrected version of the code in the second part prints a specific pattern using nested for-loops and the 'fprintf' function.

Step-by-step explanation:

The first part of the question asks for the output of executing the given MATLAB code. However, there are several syntax errors in the code which make it invalid. The correct format for assigning values to variables in MATLAB is using the '=' symbol, rather than '-'. Additionally, the code tries to access elements of a matrix 'M' that hasn't been defined. Without knowing the values of 'M', it's not possible to determine the output.

The second part of the question asks to write a MATLAB script to print a specific pattern. Here's a corrected version of the code:

<code>fprintf('12\\');
for i = 2:7
for j = 1:i
fprintf('%d', j);
end
fprintf('\\');
end</code>

This script uses nested for-loops to control the number of rows and the length of each row in the pattern. It uses the 'fprintf' function to print the numbers on each row, and the '\\' symbol to start a new line after each row.