Question

For a voltage divider bias circuit, R1 = 62KΩ, R2 = 9.1 KΩ, RE = 680 Ω, RC = 3.9 K, Vcc= 16V, β = 80, calculate S and S’.

Answer 1

In a voltage divider bias circuit, R1 and R2 are used to set the operating point of a transistor. The ratio of R2 to R1 determines the bias voltage at the base of the transistor. The values given can be used to calculate the voltage at the base of the transistor, as well as the parameters S and S' which describe the transistor's operation.

Step-by-step explanation:

In a voltage divider bias circuit, R1 and R2 are used to set the operating point of a transistor. The ratio of R2 to R1 determines the bias voltage at the base of the transistor. In this case, R1 is 62KΩ and R2 is 9.1KΩ.

To calculate the voltage at the base of the transistor, you can use the voltage divider formula: Vb = Vcc * (R2 / (R1 + R2)). Given that Vcc is 16V and R1 = 62KΩ and R2 = 9.1KΩ, you can substitute these values into the formula to calculate Vb.

Then, to find S and S', you can use the formula: S = β * (Vb / RE) and S' = β * ((Vcc - Vb) / RC), where β is the current gain of the transistor, RE is the emitter resistance, and RC is the collector resistance.