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In a cylindrical coordinate system, a 2-m-long straight wire carrying a current of 5 A in the positive z direction is located at r = 4 cm, φ = π/4, and. 1 m z 1 m.

(a) If B = ˆr0:2cosφ (T), what is the magnetic force acting on the wire?

User Irukandji
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1 Answer

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Final answer:

The magnetic force acting on the wire is 2 A · m · T · cos(π/4)ı.

Step-by-step explanation:

The magnetic force acting on a wire carrying a current in a magnetic field is given by the formula F = I * L * B * sin(θ), where I is the current, L is the length of the wire, B is the magnetic field, and θ is the angle between the current direction and the magnetic field direction.

In this case, the wire is 2 meters long and carries a current of 5 A in the positive z direction. The magnetic field is given by B = ˆr0:2cosφ (T).

To find the magnetic force, we need to calculate the components of the magnetic field in the r and φ directions, and then use the formula to find the force.

Let's calculate the components and find the magnetic force:

B = ˆr0:2cosφ (T) = 0.2cos(π/4)ı

The magnetic force is given by:

F = I * L * B * sin(θ) = (5 A)(2 m)(0.2cos(π/4)ı)(sin(90°))

Calculating the force:

F = (5 A)(2 m)(0.2cos(π/4)ı)(1)

Simplifying the calculation:

F = 2 A · m · T · cos(π/4)ı

Therefore, the magnetic force acting on the wire is 2 A · m · T · cos(π/4)ı.

User Paul Lammertsma
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