Question

An electric heater is connected to a constant 220V source and absorbs 1000 W. Subsequently, this heater is connected to a constant 110V source. What power does it absorb from the 110V source? What is the resistance of the heater?

Answer 1

The power absorbed by the heater from the 110V source would be 250 W, and the resistance of the heater is calculated to be 48.4 Ω.

Step-by-step explanation:

When an electric heater is connected to a 220V source and absorbs 1000W, this implies that the heater has a certain resistance. The formula for power, P, in terms of voltage, V, and resistance, R, is P = V2/R. Using this formula, we can calculate the resistance of the heater when connected at 220V:

P = V2/R
1000 W = (220 V)2/R
R = (220 V)2/1000 W
R = 48400 / 1000
R = 48.4 Ω

Now we can determine the power absorbed by the heater when connected to a 110V source with the same resistance. Using the formula again, we get:

P = V2/R
P = (110 V)2/48.4 Ω
P = 12100 / 48.4
P = 250 W

Hence, from the 110V source, the heater would absorb a power of 250 W. The resistance of the heater is 48.4 Ω.