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Design common emitter amplifier. Use V+=12V, V-=-12V. β=200

a)Make AC voltage gain 110 (40dB), fL=5kHz, fH=35MHz

User Summea
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Final answer:

To design a common emitter amplifier with the specified gain and frequency response, resistor values must be calculated for proper biasing and gain, and capacitor values must be selected to achieve the desired frequency response.

Step-by-step explanation:

Common Emitter Amplifier Design

To design a common emitter amplifier with an AC voltage gain of 110 (40dB), using a power supply of 12V and -12V, and a transistor with a current gain (β) of 200, you have to select the appropriate resistor and capacitor values for the amplifier circuit. The desired lower cutoff frequency (曜L) is 5kHz and the higher cutoff frequency (曜H) is 35MHz. To achieve the specified gain, careful calculations of the resistor values in the input and the load must be conducted, ensuring signals are correctly biased and amplified without distortion. Additionally, the input and output coupling capacitors, as well as the emitter bypass capacitor, must be selected to set the frequency response of the amplifier.

Remember, the gain of the amplifier (Av) is typically given by the ratio of the load resistor (RL) to the emitter resistor (RE). It is important to consider the biasing conditions to ensure the transistor operates in the active region. The selection of the coupling and bypass capacitors is based on their reactance at the cutoff frequencies, ensuring that they do not appreciably affect the amplifier's gain within the desired frequency band.

User Moobie
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