Question

Data recorded from a 400 V,50 Hz,3-phase induction motor showed when operating on full-load it took a current of 95 A at a power factor of 0.8 lagging and ran with a slip of 4%. The stator losses were recorded as 1.6 kW and the rotational losses was 0.84 kW. Calculate the:

i. input power

Answer 1

The input power of the 3-phase induction motor is approximately 64,395.09 W.

Step-by-step explanation:

A 3 phase induction motor derives its name from the fact that the rotor current is induced by the magnetic field, instead of electrical connections. The operating principle of a 3 phase induction motor is based on the production of a rotating magnetic field (r.m.f.). The input power of a 3-phase induction motor can be calculated using the formula:

Input power = √3 * Voltage * Current * Power factor

Given that the voltage is 400 V, the current is 95 A, and the power factor is 0.8 lagging, we can substitute these values into the formula to find the input power.

Input power = √3 * 400 V * 95 A * 0.8 = 64,395.09 W

Therefore, the input power of the motor is approximately 64,395.09 W.