Question

A long cylindrical conductor is made up of two concentric layers. The first has a radius of 0.002 meters, a conductivity of 3×10⁶ S/m, and is centered on the z-axis. The second layer extends from radius 0.002 to radius 0.003, with a conductivity of 6×10⁶ S/m. The wire carries a total current of 0.3 Amps. Find the value of H at a radius of 0.0022.

Answer 1

To find the value of magnetic field strength (H) at a given radius in a long cylindrical conductor with concentric layers, use Ampere's law and the given current. Use the equation B = μ₀H to find the value of H at the desired radius.

Step-by-step explanation:

To find the value of magnetic field strength (H) at a radius of 0.0022 meters, we need to use Ampere's law. Ampere's law states that the line integral of magnetic field around a closed loop is equal to the product of the current enclosed by the loop and the permeability of free space.

Given that the wire carries a total current of 0.3 Amps, we can calculate the magnetic field strength at the desired radius.

Using B = μ₀H, where B is the magnetic field strength, and μ₀ is the permeability of free space, we can find the value of H at a radius of 0.0022 meters.