Question

5 yd 15 yd find the Shaded area of each figure round your answer to the decimal place if necessary

Answer 1

Part (a);

`\begin{gathered} \text{The area of the semi-circle with a radius of 5 yds;} \\ A=\pir^2^{} \\ \text{Foe a semi-circle (}(1)/(2)\text{ circle)} \\ \text{Area}=(\pir^2)/(2) \\ \text{Area}=(3.14*5^2)/(2) \\ \text{Area}=(78.5)/(2) \\ \text{Area}=39.25yd^2 \\ \text{Area of the triangle=}(1)/(2)bh \\ b=\text{base (}15) \\ h=vertical\text{ height (10) that is radius x 2} \\ \text{Area}=(1)/(2)*15*10 \\ \text{Area}=75 \\ \text{Area of the entire figure=39.25 + 75} \\ \text{Area of the entire figure=114.25 yds}^2 \end{gathered}`

Part (b);

`\begin{gathered} \text{Area of the circle=}\pir^2 \\ \text{radius}=5\text{yds} \\ \text{Area}=3.14*5^2 \\ \text{Area}=3.14*25 \\ \text{Area}=78.5yd^2 \\ \text{Area of the triangle=}(1)/(2)* bh \\ b=\text{base (16)} \\ h=\text{vertical height (16)} \\ \text{Area}=(1)/(2)*16*16 \\ \text{Area}=128yd^2 \\ Area\text{ of shaded region=Area of triangle-Area of circle} \\ \text{Area of shaded region=128-78.5} \\ \text{Area of shaded region=}49.5yd^2 \end{gathered}`