Final answer:
In a reaction between copper and oxygen, 101.68 grams of copper will react with 0.80 mole of oxygen gas, based on the stoichiometric relationship from the balanced chemical equation.
Step-by-step explanation:
The student has asked how many grams of copper metal will react with 0.80 mole of oxygen gas. To answer this question, one must understand the stoichiometric principles of a balanced chemical equation. In this case, the equation for the reaction between copper and oxygen would be written as follows:
2 Cu (s) + O₂ (g) → 2 CuO (s)
This equation tells us that 2 moles of copper (Cu) react with 1 mole of oxygen (O₂) to produce 2 moles of copper oxide (CuO). Since the question provides 0.80 mole of oxygen gas as the reactant, we can use this stoichiometric relationship to find the amount of copper needed.
Firstly, for every 1 mole of O₂, 2 moles of Cu are required, according to the balanced equation. So, for 0.80 moles of O₂, we would need 2 x 0.80 = 1.60 moles of Cu.
Next, we convert moles of Cu to its mass using the molar mass of copper, which is approximately 63.55 g/mol. The mass of copper that will react with 0.80 moles of O₂ is:
Mass of Cu = Number of moles × Molar mass of Cu
Mass of Cu = 1.60 moles × 63.55 g/mol
Mass of Cu = 101.68 grams
Therefore, 101.68 grams of copper would react with 0.80 mole of oxygen gas under these conditions.