Final answer:
In this case, the real part of ZR₁ is 24502 [Ω] and the imaginary part of ZR₁ is 0 [Ω].
Step-by-step explanation:
To find the impedance, ZR₁, of resistor R₁ in rectangular form, we can use the formula:
ZR₁ = R₁
Given that R₁ = 24502Ω, the impedance of resistor R₁ is also equal to 24502Ω in rectangular form.
Therefore, the impedance ZR₁ of resistor R₁ in rectangular form is 24502 + 0j [Ω].
Now, let's determine the real and imaginary parts of ZR₁.
The real part of ZR₁ is the resistance, which is the same as the real part of any impedance in rectangular form. In this case, the real part of ZR₁ is 24502Ω.
The imaginary part of ZR₁ is 0, as there is no imaginary component present.
Therefore:
- Real Part of ZR₁ = 24502 [Ω]
- Imaginary Part of ZR₁ = 0 [Ω]
So, the real part of ZR₁ is 24502 [Ω] and the imaginary part of ZR₁ is 0 [Ω].
Your question is incomplete, but most probably the full question was:
Assume R₁ = 24502, L₁ = 3. 3mH, C₁ = 0.22 μF, and = 35,000 for the above circuit. Allanswers must be rounded to 2 decimal places and match the units in the square brackets.
Find the impedance, ZR₁, of resistor R₁ rectangular form (e.g. a + bj).
- Real Part of ZR1 [2]
- Imaginary Part of ZR₁ [2]