Final answer:
A single-phase half-wave rectifier with RL-load allows only the positive half-cycle of the input waveform to pass through, resulting in a pulsating DC output. The rms values on the input and output sides can be calculated using specific formulas.
Step-by-step explanation:
A single-phase half-wave rectifier with an RL-load consists of a diode and a resistor connected in series with an inductor. The rectifier allows only the positive half-cycle of the input waveform to pass through, resulting in a pulsating DC output. The rms value on the input side can be calculated using the formula Vrms = Vm/√2, where Vm is the peak voltage of the sinusoidal input waveform. On the output side, the rms value can be calculated by squaring the peak voltage, multiplying by the rectification factor (0.318), and taking the square root of the result.
The power dissipated in the load resistor can be calculated using the formula P = I^2 * R, where I is the rms current flowing through the circuit and R is the resistance. The rectification efficiency can be calculated by dividing the power dissipated in the load resistor by the power input from the source. The performance parameters include the output voltage ripple, which is the difference between the peak and minimum values of the output voltage, and the rectification factor, which is the ratio of the average value of the output voltage to the peak value of the input voltage. The ratings of the transformer and diodes depend on the current and voltage requirements of the circuit.