Final answer:
- a. The voltage gain is -2.381
- b. The input resistance is 560 kΩ.
Step-by-step explanation:
a) To calculate the voltage gain in an amplifier, we use the formula Av = -β * RB / ( (RB + β * Rin) * (VDO + |VA|) + RB * β ).
Plugging in the given values, Av = -(50 * 10³) / ( (10⁴ + 50 * 5 *10³) * (0.7 + 10) + 10⁴ * 50 ) = -2.381.
Therefore, the voltage gain is -2.381.
b) The input resistance (Rin) can be found using the formula Rin = R-in + (1 + β)*RB = 5 * 10³ + (1 + 50) * 10⁴ = 560 * 10³ ohms.
Therefore, the input resistance is 560 kΩ.
Your question is incomplete, but most probably the full question was:
|VA| = 10 V, βpnp = 50, VDO = 0.7 V, RB = 10 kΩ.
R-in=5 kΩ, R-out= 1kΩ.
Vcc=22.5 V
Note: Use ac small-scale signal analysis, and Early effect into consideration given that |VA| = 10 V.
Question:
a) The voltage gain (Av = Vout/Vin)
b) The input resistance (Rin)