Final answer:
In this case, the spectrum of the discrete-time signal x₁[n] is X(e^jω) = 1.0e^(-j0ω) - 0.5e^(-j1ω) + 0.5e^(-j2ω) + 1.0e^(-j3ω)
Step-by-step explanation:
AI-generated answer
To determine the spectrum of the discrete-time signal x₁[n] = [1.0, -0.5, 0.5, 1.0], we can use the given Discrete-time Fourier transform summation formula:
X(e^jω) = ∑[n=-∞ to ∞] x[n]e^(-jinω)
Let's substitute the values of x₁[n] into the formula and evaluate the summation step-by-step:
X(e^jω) = x[0]e^(-j0ω) + x[1]e^(-j1ω) + x[2]e^(-j2ω) + x[3]e^(-j3ω)
1. Evaluating x[0]:
X(e^jω) = 1.0e^(-j0ω)
2. Evaluating x[1]:
X(e^jω) = 1.0e^(-j0ω) - 0.5e^(-j1ω)
3. Evaluating x[2]:
X(e^jω) = 1.0e^(-j0ω) - 0.5e^(-j1ω) + 0.5e^(-j2ω)
4. Evaluating x[3]:
X(e^jω) = 1.0e^(-j0ω) - 0.5e^(-j1ω) + 0.5e^(-j2ω) + 1.0e^(-j3ω)
Now, we have the expression for X(e^jω), which represents the spectrum of the discrete-time signal x₁[n].
It is important to note that the missing value for n > [missing value] limits the range of the summation in the given formula. To provide a complete and accurate spectrum, the missing value needs to be specified. Once that value is provided, the summation can be evaluated accordingly.