46.0k views
0 votes
Line J goes through (4,-2),(6,-5), and (-2,a). Find the value of a.

User Sugan S
by
7.2k points

1 Answer

5 votes

Final answer:

The value of 'a' is determined to be 7 by first calculating the slope of the line that passes through the given points, then finding the line's equation, and finally substituting x = -2 into this equation to solve for 'a'.

Step-by-step explanation:

To find the value of a for the point (-2, a) that lies on line J, which also passes through the points (4,-2) and (6,-5), we need to determine the equation of the line and then use it to solve for a when x equals -2.

First, let's calculate the slope of the line (m) using the two given points:

m = (y2 - y1) / (x2 - x1)

m = (-5 - (-2)) / (6 - 4)

m = (-3) / 2

m = -1.5

Now that we have the slope, we can use point-slope form to find the equation of the line:

y - y1 = m(x - x1)

Let's use the point (4, -2) for this equation:

y - (-2) = -1.5(x - 4)

y + 2 = -1.5x + 6

y = -1.5x + 4

Finally, substitute x = -2 into the equation to find the y-coordinate:

a = -1.5(-2) + 4

a = 3 + 4

a = 7

Therefore, the value of a is 7.

User Kevhender
by
7.5k points