Question

"The voltage source is 5 + 6sin(377t) V. What is the reading of the voltmeter at the AC scale setting?

R1 = 1 kΩ
R2 = 3 kΩ

(a) 4.92 V
(b) 1.64 V
(c) 3.75 V
(d) 5.83 V"

Answer 1

To find the reading of the voltmeter at the AC scale setting, we need to calculate the voltage across the resistor using Ohm's Law. Using the values of the resistors in the circuit, we can calculate the AC current and then determine the reading of the voltmeter.

Step-by-step explanation:

To find the reading of the voltmeter at the AC scale setting, we need to determine the voltage across the resistor. In this case, the voltage source is given as 5 + 6sin(377t) V. The AC voltage given by the source can be represented as V = Vo sin(2πft), where Vo is the peak voltage and f is the frequency in hertz.

Using this information and the values of R1 and R2, we can calculate the voltage across the resistor using Ohm's Law: V = I * R. The AC current in this circuit can be found by dividing the AC voltage by the total resistance (R = R1 + R2). Once we know the AC voltage across the resistor, we can calculate the reading of the voltmeter at the AC scale setting.

Using the given values of R1 = 1 kΩ and R2 = 3 kΩ, the answer is (b) 1.64 V.