204k views
4 votes
Required information: An AC motor with impedance Z_L = (6.0 + j0.40) ohms is supplied by an RMS value of 220-V, 60-Hz source.

User Hoa Nguyen
by
7.6k points

1 Answer

0 votes

Final answer:

To calculate the RMS current in an AC motor with impedance Z_L = (6.0 + j0.40) ohms connected to a 220-V, 60-Hz source, we use the AC version of Ohm's law, where I_rms is the RMS current, V_rms is the RMS voltage, and Z is the impedance.

Step-by-step explanation:

The student's question pertains to the calculation of the current in an AC motor with a given impedance when supplied by a 220-V, 60-Hz source. The solution involves applying the AC version of Ohm's law. The impedance mentioned, ZL = (6.0 + j0.40) ohms, represents a complex impedance with a real part and an imaginary part, corresponding to the resistance and reactance of the motor, respectively.

The formula for computing the RMS current (Irms) is as follows:

Irms = Vrms / Z

Where Irms is the RMS current, Vrms is the RMS voltage of the source, and Z is the impedance. Inserting the given values into the formula will yield the RMS current flowing through the motor.

User Sean Taylor
by
7.6k points