Final answer:
The question deals with calculating the current and power dissipation in a short-circuited winding under a 240 V AC supply using the resistance value. The interpretation of Ohm's law and power formulas is critical to finding the values.
Step-by-step explanation:
The question involves understanding electric circuits, particularly the concepts of resistance, current, and power in context with alternating current (AC). When a 240 V AC is applied to a winding with another winding short-circuited, it creates a scenario of a short circuit through which AC passes. According to Ohm's law, the current I in a circuit is inversely proportional to the resistance R (I = V/R) and the power dissipated P can be calculated using the relation (P = VI), where V is the voltage. For a short circuit with a resistance of 0.250 Ω, the current can be calculated by dividing the voltage by resistance. Assuming no impedance and perfect conductive conditions, the power dissipation can then be computed using the product of the current and voltage.