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For a charge particle travelling at velocity u and mass m in presence of magnetic field, will rotate in a L armor radius, when centrifuge and Lorenz forces are equal. Consider an electron and an argon ion pass through a magnetic flux density of 0.01 T. Both particles are accelerated through a potential difference of 1 V. Find Larmor radius of electron and argon ion particles.

User Mintu
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Final answer:

The Larmor radius is the radius of curvature of the path of a charged particle in a magnetic field. It can be determined using the formula r = (m*v) / (|q| * B), where r is the Larmor radius, m is the mass of the particle, v is the velocity of the particle perpendicular to the magnetic field, q is the charge of the particle, and B is the magnetic flux density.

Step-by-step explanation:

The Larmor radius, denoted as r, is the radius of curvature of the path of a charged particle traveling at velocity u in the presence of a magnetic field. When the centrifugal and Lorentz forces are equal, the particle will move in a circular path with a radius equal to the Larmor radius. To determine the Larmor radius of the electron and argon ion particles, we can use the formula:

r = (m*v) / (|q| * B)

Where r is the Larmor radius, m is the mass of the particle, v is the velocity of the particle perpendicular to the magnetic field, q is the charge of the particle, and B is the magnetic flux density.

Given that the electron and argon ion pass through a magnetic flux density of 0.01 T and are accelerated through a potential difference of 1 V, we can find their Larmor radii using the given formula and the respective masses and charges of the particles.

User Marijo
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