Question

For the following circuit,find the Thevenin and Norton equivalents at terminals a-b

________ 6Ω ________ 14Ω ________ 5Ω ________
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| |
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| 14V |
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| 1A |
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|______ 3A ________|_________________________|
a b

Answer 1

The Thevenin equivalent for the circuit at terminals a-b is a voltage source of 14V in series with a 25Ω resistor. The Norton equivalent is a current source of 1A in parallel with a 25Ω resistor.

Step-by-step explanation:

The first step in finding the Thevenin and Norton equivalents is to calculate the equivalent resistance of the circuit. In this case, the three resistors in series have resistances of 6Ω, 14Ω, and 5Ω. To find the equivalent resistance, you add the individual resistances: 6Ω + 14Ω + 5Ω = 25Ω.

The Thevenin equivalent is a voltage source in series with the equivalent resistance. So the Thevenin equivalent voltage is the open circuit voltage, which is 14V in this case. Therefore, the Thevenin equivalent for the circuit at terminals a-b is a voltage source of 14V in series with a 25Ω resistor.

The Norton equivalent is a current source in parallel with the equivalent resistance. The Norton equivalent current is the short circuit current, which is 1A in this case. So the Norton equivalent for the circuit at terminals a-b is a current source of 1A in parallel with a 25Ω resistor.