Final answer:
The frequency of the heterozygous (Nn) genotype in the population is 96%.
Step-by-step explanation:
Given that approximately 4% of the turtles in the pond show the recessive phenotype long nose (nn), we can determine the frequency of the heterozygous (Nn) individuals in the population by subtracting the frequency of the recessive phenotype from 100%.
The frequency of the heterozygous genotype (Nn) can be calculated as:
- Frequency of nn = 4%
- Frequency of Nn = 100% - Frequency of nn = 100% - 4% = 96%
Therefore, the frequency of the heterozygous (Nn) genotype in the population is 96%.