Question

A 50 Hz, 18 kVA, 525/105 V conventional transformer, is to be used to supply power from a 630 V supply to a 525 V load. Consider the transformer to be ideal, and assume that all insulation can handle 630 V. Calculate the maximum secondary current under these conditions.

Answer 1

The maximum secondary current that the transformer can supply to a 525 V load when connected to a 630 V supply is approximately 34.29 A.

Step-by-step explanation:

The question asks us to calculate the maximum secondary current of a 50 Hz, 18 kVA, 525/105 V conventional transformer when it is used to supply power from a 630 V supply to a 525 V load assuming the transformer is ideal. To find the maximum secondary current (I2max), we use the power equation of a transformer: P = V2 × I2. Since we know the power rating (P) of the transformer and the secondary voltage (V2), we can rearrange the equation to solve for the maximum secondary current (I2max): I2max = P / V2. Plugging the known values into the equation gives us: I2max = 18,000 VA / 525 V, which results in approximately 34.29 A as the maximum secondary current.